Solving:$$ \frac{3}{7}-\frac{x-1}{2}-(2-x)=\frac{3x-4}{14} $$
Could someone walk me through this, or what I'm doing wrong? I do the parenthesis, and get:
$$
\frac{3}{7}-\frac{x-1}{2}-2+x=\frac{3x-4}{14}
$$
Then I multiply everything by $14$, divide the fractions and have $6-7x-28+14x=3x-4$. Add up this and $7x-29=3x-4$. I end up with $4x=25$. Which doesn't make sense, since $x$ should equal $11/4$.
I've been going through the steps myself so long I think I'm going blind for my own mistake.
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