If $x\neq0$, how to find the reciprocal of $x$ only by using trigonometric functions and inverse trigonometric functions?
I have found only one answer, which is;
$\tan (\cos ^{-1}(\sin(\tan^{-1}(x))))=\frac{1}{x}$.
Is there any other answer?
Answer
HINT
Recall that
$$\arctan x = \frac{\pi}2-\arctan \frac1x$$
$$\arctan x = -\frac{\pi}2-\arctan \frac1x$$
No comments:
Post a Comment