I need to check if
limn→∞nn√n!
converges or not. Additionally, I wanted to show that the sequence is monotonically increasing in n and so limit exists. Any help is appreciated. I had tried taking log and manipulating the sequence but I could not prove monotonicity this way.
Answer
Use Stirling's approximation:
n!∼√2πn(ne)n
and you'll get
limn→∞n(n!)1/n=limn→∞n(√2πn(ne)n)1/n=limn→∞n(2πn)1/2n(ne)=limn→∞e(2πn)1/2n=e,
because limn→∞(2πn)1/2n=limn→∞n1/n=1.
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