Monday, 17 February 2014

algebra precalculus - Which values of n allow for n-tuples of consecutive natural numbers that sum to a square?

So if we take examples, we can see that any odd number (2n+1)2=(n+1)+(n+2)++(3n+1). This is backwards though, because I'm trying to find out which (if not all) lengths of consecutive integers (e.g pairs, triplets etc) can have a square sum. Any ideas?

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real analysis - How to find limhrightarrow0fracsin(ha)h

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