Wednesday, 26 February 2014

sequences and series - Consider the geometric progression ...



I think I'm on the right track with this but not entirely confident.




a1=4 , a2=4z , a3=4z2, ...




  1. The 6th element a6

  2. The sum of the first 7 elements



I'm sure this works differently to arithmetic progression and uses ratios but a little stuck even with Googling like mad.



Thanks in advance.



Answer



Okay, so we need to find out what there is in common( common ratio). You do this by dividing. notice 4z/4=z,4z2/4z=z

so it is clear that our formula is an=4zn1



So what is a6?



a6=4z61=4z5



To sum, we use the formula n1k=0(ark)=a(1rn1r)



Where a is the first term in the series, and r is common ration. n is what you want to sum up to.




Specifically, for the first 7 elements, we have n=7,



so 6k=0(4zk)=4(1z71z)


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