Using the squeeze theorem, prove the following:
If limn→∞|an|=0, then \lim_{n\rightarrow\infty}a_n = 0.
Let f(x) = |a_n|. Let g(x) = a_n such that \forall x : g(x) \leq f(x). How do I continue this proof using the squeeze theorem? I want to construct a function h(x) that lies in between those two functions.
Answer
Hint : -|x|\le x\le |x|{}{}{}{}{}{}
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