Trying to prove that if f is one-to-one, then $$f\left(\bigcap\{U_\alpha:\alpha \in \Lambda\}\right)=\bigcap\{f(U_\alpha):\alpha\in\Lambda\}$$
I am able to prove that: $$f\left(\bigcap\{U_\alpha:\alpha \in \Lambda\}\right)\subseteq\bigcap\{f(U_\alpha):\alpha\in\Lambda\}$$
However, I do not really know where to begin the proof for:
$$\bigcap\{f(U_\alpha):\alpha\in\Lambda\}\subseteq f\left(\bigcap\{U_\alpha:\alpha \in \Lambda\}\right)$$
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