Trying to prove that if f is one-to-one, then f(⋂{Uα:α∈Λ})=⋂{f(Uα):α∈Λ}
I am able to prove that: f(⋂{Uα:α∈Λ})⊆⋂{f(Uα):α∈Λ}
However, I do not really know where to begin the proof for:
⋂{f(Uα):α∈Λ}⊆f(⋂{Uα:α∈Λ})
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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