Problem: Prove $log$$_2$($3$) is irrational using the Fundamental Theorem of Arithmetic.
What I have so far:
Proof: Suppose $log$$_2$($3$) $\in$ $\mathbb Q$
Then there are $p,q$ $\in$ $\mathbb Z$ , $q$$\neq$$0$ s.t. $log$$_2$($3$)=$\frac pq$
Then $2$$^p$ $=$ $3$$^q$
This is where I get stuck because I'm not sure how to incorporate the Fundamental Theorem of Arithmetic.
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