Wednesday, 20 August 2014

real analysis - If a an diverges, so anrightarrow+infty, how to find sequence bn such that $sum |b_n|



If we are given any sequence of real numbers {an} diverges, so an+, how can we find a sequence {bn} such that |bn| converges but |an||bn| diverges?



I want to use this fact in another problem but don't immediately see how to prove it.


Answer



Just pick a subsequence such that ank>k, and then let bnk=1/k2, and bn=0 if n is not an index in that subsequence.


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