If we are given any sequence of real numbers $\{a_n\}$ diverges, so $a_n \rightarrow + \infty$, how can we find a sequence $\{b_n\}$ such that $\sum |b_n|$ converges but $\sum |a_n||b_n|$ diverges?
I want to use this fact in another problem but don't immediately see how to prove it.
Answer
Just pick a subsequence such that $a_{n_k} > k$, and then let $b_{n_k} = 1/k^2$, and $b_n = 0$ if $n$ is not an index in that subsequence.
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