Saturday 30 August 2014

trigonometry - Can we always use Euler's formula for complex numbers?




I was thinking of this today as I was looking over my complex analysis notes.



If you have some complex number $z$, then we can define it using Euler's formula as $z=a+ib=\cos\theta+i \sin\theta$. Say we have the case that $z=3+4i=25(\cos\theta+i\sin\theta)$. Then $25\cos \theta=3$, and $25\sin\theta=4$. But this would mean that



$$\theta=\cos^{-1}\left(\frac{3}{25}\right) =\sin^{-1}\left(\frac{4}{25}\right).$$



How can this be true if $\cos^{-1}\left(\frac{3}{25}\right)=83.107 \text{ degrees}$ and $\sin^{-1}\left(\frac{4}{25}\right)=9.206 \text{ degrees}$? Does this mean that we can only have certain values of $z$ in order to use Euler's formula ?


Answer



For $z=3+4i$;
$$r=\sqrt{3^2+4^2}=5$$

$$\theta=\tan^{-1}(\frac{4}{3})\approx0.9273^c$$



Hence $z=5(\cos[0.9273]+i\sin[0.9273])$



Note via use of the $3,4,5$ triangle, we can tell that $\cos\theta=\frac{3}{5}$ and $\sin\theta=\frac{4}{5}$.



You simply missed the fact that you need to square root for $r$.


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