Monday, 4 July 2016

complex analysis - Prove that sin(piz) can be written as infinite product

Prove that
sin(πz)=πzn=1(1z2n2)zC



The hint I had it's to use the Fourier series, but I really don't see how.
Any suggestions? Thanks in advance!

No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find lim without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...