lim Hi, could someone explain to me how I can solve that limits, i thought that i could studying L_2=\lim_{(x,y) \rightarrow (0,0)} \frac{x}{\sqrt{x^2+y^2}} and do a\cos(L_2), but I dont know if this way it is correct, thanks
Answer
HINT:
Tranform to polar coordinates with x=\rho \cos \phi and y=\rho \sin \phi. Then \sqrt{x^2+y^2}=\rho.
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