lim(x,y)→(0,0)acos(x√x2+y2)
Hi, could someone explain to me how I can solve that limits, i thought that i could studying L2=lim(x,y)→(0,0)x√x2+y2 and do acos(L2), but I dont know if this way it is correct, thanks
Answer
HINT:
Tranform to polar coordinates with x=ρcosϕ and y=ρsinϕ. Then √x2+y2=ρ.
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