Wednesday, 2 November 2016

sequences and series - Result of the product 0.9times0.99times0.999times...



My question has two parts:





  1. How can I nicely define the infinite sequence 0.9, 0.99, 0.999, ? One option would be the recursive definition below; is there a nicer way to do this? Maybe put it in a form that makes the second question easier to answer.
    si+1=si+910i2, s0=0.9
    Edit: Suggested by Kirthi Raman:
    (si)i1=110i


  2. Once I have the sequence, what would be the limit of the infinite product below? I find the question interesting since 0.999...=1, so the product should converge (I think), but to what? What is the "last number" before 1 (I know there is no such thing) that would contribute to the product?
    i=1si



Answer



To elaborate, and extend on GEdgar's answer: there is what is called the q-Pochhammer symbol




(a;q)n=n1k=0(1aqk)



and (a;q) is interpreted straightforwardly. The product you are interested in is equivalent to (110;110)0.8900100999989990000001.



One can also express the q-Pochhammer symbol (q;q) in terms of the Dedekind η function η(τ) or the Jacobi ϑ function ϑ2(z,q); in particular we have



(110;110)=2410η(ilog102π)=24103ϑ2(π6,1610)







I might as well... there is the following identity, due to Euler (the pentagonal number theorem):



(q;q)=j=1(1qj)=k=(1)kqk(3k1)2



which, among other things, gives you a series you can use for quickly estimating your fine product:



(110;110)=1+k=1(1)k(10k2(3k+1)+10k2(3k1))



Three terms of this series gives an approximation good to twenty digits; five terms of this series yields a fifty-digit approximation.



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