My question has two parts:
How can I nicely define the infinite sequence 0.9, 0.99, 0.999, …? One option would be the recursive definition below; is there a nicer way to do this? Maybe put it in a form that makes the second question easier to answer.
si+1=si+9⋅10−i−2, s0=0.9
Edit: Suggested by Kirthi Raman:
(si)i≥1=1−10−iOnce I have the sequence, what would be the limit of the infinite product below? I find the question interesting since 0.999...=1, so the product should converge (I think), but to what? What is the "last number" before 1 (I know there is no such thing) that would contribute to the product?
∞∏i=1si
Answer
To elaborate, and extend on GEdgar's answer: there is what is called the q-Pochhammer symbol
(a;q)n=n−1∏k=0(1−aqk)
and (a;q)∞ is interpreted straightforwardly. The product you are interested in is equivalent to (110;110)∞≈0.8900100999989990000001.
One can also express the q-Pochhammer symbol (q;q)∞ in terms of the Dedekind η function η(τ) or the Jacobi ϑ function ϑ2(z,q); in particular we have
(110;110)∞=24√10η(ilog102π)=24√10√3ϑ2(π6,16√10)
I might as well... there is the following identity, due to Euler (the pentagonal number theorem):
(q;q)∞=∞∏j=1(1−qj)=∞∑k=−∞(−1)kqk(3k−1)2
which, among other things, gives you a series you can use for quickly estimating your fine product:
(110;110)∞=1+∞∑k=1(−1)k(10−k2(3k+1)+10−k2(3k−1))
Three terms of this series gives an approximation good to twenty digits; five terms of this series yields a fifty-digit approximation.
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