I would like to calculate the Laurent series of log(z)sin(1z−1)
I have developed separately logz et the sinus and tried to multiplied them terms by terms but it is complicated. Is there another simplier way?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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