I really can't remember (if I have ever known this): which series is this and how to demonstrate its solution?
n∑i=1i=n(n+1)2
Answer
This is an Arithmetic Series starting from 1 with difference 1.
n∑i=1i=1+2+3+4+...+n=n(n+1)2
1#Check this out.
2#There's one another related one.
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