Saturday, 8 February 2014

calculus - Cauchy-Schwarz inequality application



I am having trouble verifying the first step where the author makes use of Cauchy-Schwarz inequality.
https://gbas2010.wordpress.com/2011/10/16/inequality-53-vo-quoc-ba-can/




I am unsure how he chooses the terms from $( a + b + c )$ to square and multiple on the LHS.


Answer



He is using the two variable form of the inequality, that is
\begin{equation}
(x^2 + y^2)(z^2 + w^2) \geq (xz + yw)^2
\end{equation}
Now set $x = \sqrt{a^2 + b^2}$, $y = c$, $z = \frac{a + b}{\sqrt{a^2 + b^2}}$ and $w = 1$ and we get
\begin{align}
((\sqrt{a^2 + b^2})^2 + c^2)((\frac{a + b}{\sqrt{a^2 + b^2}})^2 + 1 ) &\geq (\sqrt{a^2 + b^2} \frac{a + b}{\sqrt{a^2 + b^2}} + c \cdot 1)^2\\
(a^2 + b^2 + c^2)(\frac{(a + b)^2}{a^2 + b^2} + 1 ) &\geq (a + b + c)^2

\end{align}
Which is the first step of the solution.


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