I need to show that
∫∞0sin4xx4dx=π3
I have already derived the result ∫∞0sin2xx2=π2 using complex analysis, a result which I am supposed to start from. Using a change of variable x↦2x :
∫∞0sin2(2x)x2dx=π
Now using the identity sin2(2x)=4sin2x−4sin4x, we obtain
∫∞0sin2x−sin4xx2dx=π4
π2−∫∞0sin4xx2dx=π4
∫∞0sin4xx2dx=π4
But I am now at a loss as to how to make x4 appear at the denominator. Any ideas appreciated.
Important: I must start from ∫∞0sin2xx2dx, and use the change of variable and identity mentioned above
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