Sunday, 10 August 2014

calculus - Limit of the sequence an=frac1+sqrt2+sqrt3+cdots+sqrtnnsqrtn



I have to solve this sequence:



an=1+2+3++nnn



As a tip I've been told to use Stoltz-Cesaro for sequance of this form : an=xnyn



So I did Stoltz-Cesaro

xnxn1ynyn1 and I end up with: nnn(n1)n1. I am stuck at this point, can you please give me some tips on what to do next? Thank you.


Answer



A possible approach:



nnn(n1)n1=1n(n1)11n=



=n+(n1)11nn2(n1)2(11n)=n+(n1)11nn2n2+n+2n21+1n=



(1+11n)n11n3n3+1nn23


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...