I have to solve this sequence:
an=1+√2+√3+⋯+√nn√n
As a tip I've been told to use Stoltz-Cesaro for sequance of this form : an=xnyn
So I did Stoltz-Cesaro
xn−xn−1yn−yn−1 and I end up with: √nn√n−(n−1)√n−1. I am stuck at this point, can you please give me some tips on what to do next? Thank you.
Answer
A possible approach:
√nn√n−(n−1)√n−1=1n−(n−1)√1−1n=
=n+(n−1)√1−1nn2−(n−1)2(1−1n)=n+(n−1)√1−1nn2−n2+n+2n−2−1+1n=
(1+√1−1n)n−√1−1n3n−3+1n→n→∞23
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