Given the series
∞∑n=1(−1)nsin(nπ)
I need to test for convergence/divergence. I think the divergent test might work here. I could see that the limn→∞(−1)nsin(nπ) might not exist, so the series is divergent. But I still need a solid proof here.
Any help is appreciated. Thanks.
Answer
I guess the standard argument should work. If Sn=∑nk=0ak converges then ak→0. The necessary condition is not satisfied.
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