Friday, 1 July 2016

summation - Sum of Arithmetic-Geometric Series




So I am having trouble getting the sum of the series:



1+2(32)+3(3222)+...+k(3k12k1)




I cant figure out for the life of me how to figure out the sum of this.


Answer



Let
S=1+a+a2++ak=1ak+11a


Differentiating for a we get
S=1+2a+3a2++kak1=ak(kak1)+1(a1)2

It is then obvious that for a=32 we get the wanted sum, that is
1+2(32)++k(32)k1=(32)k(2k4)+4


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