So I am having trouble getting the sum of the series:
1+2(32)+3(3222)+...+k(3k−12k−1)
I cant figure out for the life of me how to figure out the sum of this.
Answer
Let
S=1+a+a2+⋯+ak=1−ak+11−a
Differentiating for a we get
S′=1+2a+3a2+⋯+kak−1=ak(ka−k−1)+1(a−1)2
It is then obvious that for a=32 we get the wanted sum, that is
1+2(32)+⋯+k(32)k−1=(32)k(2k−4)+4
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