A completes 36% work in 12 days.
B is twice as fast as A.
C is twice as fast as B.
How many approx days are required for finishing the remaining 64% work if all of them work together.?
a)2 b)4 c)6 d)8
Answer is a but i am getting option b...
i have shown my solution below..
Answer
work done by A in 1 day is 36/1200
work done by B in 1 day is 36/600
work done by C in 1 day is 36/300
work done by A,B,C in 1 day is 36/1200 + 36/600 + 36/300
Thus A,B,C need 1/(36/1200 + 36/600 + 36/300) days to finish 100% work
i.e. A,B,C need 4.76 days to finish 100% work
Thus A,B,C need 64x4.76/100 days to finish 64% work
i.e. A,B,C need 3.04 days to finish 64% work
Thus answer should be b as 3.04 which is closer to 4 than 2..
But the answer was given as a... ? vch 1 do u feel is correct
pls Help...
No comments:
Post a Comment