Solving a basic linear congruence

I have been tasked with solving a linear congruence:

$$-12x\equiv-3\pmod{26}$$

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How do I do this? I've never done linear congruences with minus signs so I'm quite confused.

Usually I would find the inverse of the LHS and multiply the RHS by the inverse however obviously since we have a negative number, the number isn't in $\mathbb{Z}_{26}$ so we can't find an inverse.

Answer

For some integer $k$,
$$\begin{align*} -12x&\equiv -3 \pmod{26}\\ -12x &= -3 + 26k \end{align*}$$
The left hand side is divisible by $2$, but the right hand side is not, so there is no solution for $x$.