Show that
∫∞−∞x2dx(x2+1)2(x2+2x+2)=7π50
So I figured since it's an improper integral I should change the limits
limm1→−∞∫0m1x2dx(x2+1)2(x2+2x+2)+limm2→∞∫m20x2dx(x2+1)2(x2+2x+2)
I'm however not sure how to evaluate this. Any help would be great - thanks.
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