Wednesday, 17 August 2016

real analysis - Finding limxrightarrow0+fracxx1x



I'm trying to solve the limit limx0+xx1x



I think we should use L'Hospital rule and the limit becomes



limx0+xx(logx+1)=limx0+logx+1xx=+




Is it right?



I've tried to modify the form and not use L'Hospital's rule but without success.


Answer



Without the Hospital's rule: xx1x=xx1xxx=exlnx1xlnxlnx1xx+.


No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...