Tuesday 30 August 2016

calculus - Limit of exponential functions

Why





I know that for calculating this limit a Taylor series expansion around x=0 is done for the function, and after taking the limit of it's Taylor series expansion the result of the limit is obtained.




My question is why in this case a Taylor series expansion must be done before taking the limit?

No comments:

Post a Comment

real analysis - How to find $lim_{hrightarrow 0}frac{sin(ha)}{h}$

How to find $\lim_{h\rightarrow 0}\frac{\sin(ha)}{h}$ without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...