Consider we has a polynomial P=(x−β)g(x), where β←Zp, p is a large prime, and g(x) is a non-zero polynomial.
Here degree of P is fixed n. We evaluate P at (x1,...,xn+1). So we get (y1,...,yn+1) where P(xi)=yi.
Question: Given n pairs (x1,y1),...,(xn,yn) we interpolate a polynomial P′ of degree at most n−1.What is the probability that P′ has root β too?
TBN: xi≠β
edit: xi≠xj and xi∈Zp but xi's are not necessarily picked uniformly at random
Answer
Since P has degree n and P′ has degree n−1 at most, P−P′ has degree n, so it has n distincts roots at most. Since P(xi)=yi=P′(xi) for i∈{1,…,n}, P′(β)≠P(β)=0, so P′ cannot have β has a root.
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