Consider the equation:
2√2x+√2x+3=√3x+2+√6x+20.
Find a trick ( if exists ) which allows to solve it elegantly i.e. with avoiding the systematic squaring.
(The systematic squaring inevitably leads to a fourth-degree equation:
0=207x4−12564x3+27738x2+231084x−40401=9(23x2−1258x−4489)(x2−6x+1),
so the answer is
x=629+√49888823.
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