Sunday, 9 February 2014

algebra precalculus - Looking for a trick to solve 2sqrt2x+sqrt2x+3=sqrt3x+2+sqrt6x+20

Consider the equation:



22x+2x+3=3x+2+6x+20.



Find a trick ( if exists ) which allows to solve it elegantly i.e. with avoiding the systematic squaring.



(The systematic squaring inevitably leads to a fourth-degree equation:



0=207x412564x3+27738x2+231084x40401=9(23x21258x4489)(x26x+1),
so the answer is
x=629+49888823.

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