What is the sum of the second numbers in the first 100 rows of Pascal's triangle (excluding the first row, the row containing a single 1)? The sum should be from the second to the hundredth row.
Starting from the second row, I initially thought this meant you count from the left two numbers. So it would be 1+2+3+4+⋯+99 This means I get 4950. I thought this would be too simple of a solution.
Could someone tell me if the addition I did above is all the question is asking from me?
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