Friday, 16 June 2017

sequences and series - Show that an defined by an+1=fracan+2an+1 converges

Suppose a0 is an arbitrary positive real number. Define the sequence {an} by an+1=an+2an+1 for all n0. I have to prove that {an} converges.



My attempt: If a=lim exists, then it should be a solution to a=\frac{a+2}{a+1} which is \sqrt2. Thus I need to show that |\sqrt2 - a_n| gets arbitrarily small for large n. I tried to prove that |\sqrt2-a_n|<|\sqrt2-a_{n-1}| but couldn't.

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