Monday, 26 June 2017

calculus - Evaluate integral



How do I evaluate the following integral, the answer according to Wolfram Alpha is 2, but I keep on getting 0 after using integration by parts.12x2e|x| dx


Answer



12x2e|x|dx=120x2exdx+120x2exdx=0x2exdx=[x2(ex)]0+20xexdx=0+2[x(ex)]0+20exdx=0+0+2[(ex)]0=2


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