Sunday, 25 June 2017

general topology - bijective continuous function on $mathbb R^n$ not homeomorphism?



Suppose we have a bijective continuous map $\mathbb{R}^n\to\mathbb{R}^n$ (relative to the standard topology). Must this map be a homeomorphism?



I have little doubt about this. I think that if it happens, I guess it's true, I've heard it is true, but I can not prove it.


Answer



Every such map is open according to invariance of domain and is therefore a homeomorphism. However, invariance of domain is highly nontrivial to prove with elementary topological methods. The slickest way would be via algebraic topology.



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