Saturday, 13 August 2016

elementary number theory - Finding remainder on division by 2014

I'm trying to find the remainder when $6^{936}$ is divided by $2014$



I started thinking I could use Euler's theorem but then noticed that $6$ isn't prime, I then tried to split it into $6=2 \times 3$ but have got stuck now and don't know how to continue?

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