limits - Evaluating $lim_{ntoinfty}left(frac{n+3}{n+1}right)^{2n}$

I am having a hard time finding the next step on this.

Can someone tell me what is the next step and explain to me
in non-mathematical terms what I am supposed to do when I reach

this examples at this place ?

$$\begin{align*} \lim_{n\to\infty}\left(\dfrac{n+3}{n+1}\right)^{2n} &=\lim_{n\to\infty}\left(\dfrac{n+1+2}{n+1}\right)^{2n}\\ &=\lim_{n\to\infty}\left(1+\dfrac{2}{n+1}\right)^{2n}\\ &=\lim_{n\to\infty}\left(1+\dfrac{2}{n+1}\right)^{?} \end{align*}$$

Answer

$$\lim_{n\to\infty}\left(\dfrac{n+3}{n+1}\right)^{2n} = \lim_{n\to\infty}\left ( \frac{n\cdot \left (1+\frac{3}{n} \right )}{n\cdot\left (1+\frac{1}{n} \right ) } \right )^{2n} = \lim_{n\to\infty}\left ( \frac{\left (1+\frac{3}{n} \right )}{\left (1+\frac{1}{n} \right ) } \right )^{2n} = \lim_{n\to\infty}\frac{\left (\left ( 1+\frac{3}{n} \right )^{n}\right)^2}{\left (\left ( 1+\frac{1}{n} \right )^{n} \right )^{2}} =$$ $$= \frac{\left (e^{3} \right )^{2}}{\left (e^{1} \right )^{2}} = \frac{e^6}{e^2} = e^{6-2} = e^4.$$