Monday, 16 January 2017

real analysis - How to integrate intinfty0left(fracsin(x)xright)mdx?




How to evaluate L(m):=0(sin(x)x)mdx?
I am familiar with the case m=1, but what about the general one?


Answer



I recently explained this issue to a student in the following way:
Let f(x)=sinm(x) where m>1. Integration by parts m1 times gives the formula



0f(x)xmdx=1(m1)!0f(m1)(x)xdx.




Now we have the formulae



sin2n(x)=122n1n1k=0(1)nk(2nk)cos((2n2k)x)+122n(2nn)sin2n1(x)=122n2n1k=0(1)nk1(2n1k)sin((2n2k1)x).



Differentiate the former 2n1 times and the latter 2n2 times to obtain with the very first equation




L(2n)=π22n(2n1)!n1k=0(1)k(2nk)(2n2k)2n1L(2n1)=π22n1(2n2)!n1k=0(1)k(2n1k)(2n2k1)2n2,



since



0sin((2n2k)x)xdx=0sin(x)xdx=π2.




This yields in a campact shape



L(m)=π2m(m1)!m2k=0(1)k(mk)(m2k)m1.


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