A question that has been puzzling me for quite some time now:
Why is the value of the Riemann Zeta function equal to 0 for every even negative number?
I assume that even negative refers to the real part of the number, while its imaginary part is 0.
So consider −2 for example:
f(−2)=∑∞n=11n−2=11−2+12−2+13−2+⋯=12+22+32+⋯=∞
What am I missing here?
Answer
The Zeta function is defined as ζ(s)=∑n≥1n−s only for s∈C with ℜ(s)>1!
The function on the whole complex plane (except a few poles) is the analytic continuation of that function.
On the Wikipedia page, you can find the formula:
ζ(s)=2s−1s−1−2s∫∞0sin(sarctant)(1+t2)s2(eπt+1)dt
for s≠1. Maybe working on this integral for s a negative integer will give you the result.
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