I tried to solve
limx→∞xx−sinx.
After dividing by x I got that it equals to:
limx→∞11−sinxx.
Now, using L'hopital (0/0) I get that
limx→∞sinxx=limx→∞cosx
and the lim at infinity for cosx is not defined. So basically I get that the overall limit of
limx→∞xx−sinx
is 1 or not defined?
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