Give a precise meaning to evaluate the following:
√1+√1+√1+√1+⋯
Since I think it has a recursive structure (does it?), I reduce the equation to
p=√1+p
p2=1+p
p2−p−1=0
p=1±√52
Did I do this right?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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