For n≥1, is the sequence (xn)∞n=1 where:
xn=1+1√2+...+1√n−2√n convergent?
I started with xn+1−xn=√n(n+1)−(2n+1)√n+1≤0 since geometric mean does not exceed algebraic mean, thus decreasing, but what about convergence?
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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