I am trying to understand the interpretation of sinA2 and cosA2 in terms of sinA from my book, here is how it is given :
We have (sinA2+cosA2)2=1+sinA and (sinA2−cosA2)2=1−sinA
By adding and subtracting we have 2⋅sinA2=±√1+sinA±√1−sinA ---- (1) and 2⋅cosA2=∓√1+sinA∓√1−sinA ---(2)
I have understood upto this far well,
Now they have broke the them into quadrants :
In 1st quadrant :
2⋅sinA2=√1+sinA−√1−sinA
2⋅cosA2=√1+sinA+√1−sinA
In 2nd quadrant :
2⋅sinA2=√1+sinA+√1−sinA
2⋅cosA2=√1+sinA−√1−sinA
In 3rd quadrant :
2⋅sinA2=√1+sinA−√1−sinA
2⋅cosA2=√1+sinA+√1−sinA
In 4th quadrant :
2⋅sinA2=−√1+sinA−√1−sinA
2⋅cosA2=−√1+sinA+√1−sinA
Now, In knew the ALL-SINE-TAN-COSINE rule but still I am not able to figure out how the respective signs are computed in these (above) cases.
Answer
The easiest way of computing the signs is to make them match; we know that sin x > 0 if 0 < x < π and that cos x > 0 if -π/2 < x < π/2. Knowing whether sin A is greater than 0 or less than zero tells you whether √1−sinA is greater or less than √1+sinA; that in turn lets you figure out what the overall sign on all of the right-hand terms is, and each quadrant corresponds to one of the four positive/negative pairs on the right-hand terms.
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