Monday, 28 September 2015

trigonometry - Expressions of sinfracA2 and cosfracA2 in terms of sinA



I am trying to understand the interpretation of sinA2 and cosA2 in terms of sinA from my book, here is how it is given :



We have (sinA2+cosA2)2=1+sinA and (sinA2cosA2)2=1sinA




By adding and subtracting we have 2sinA2=±1+sinA±1sinA ---- (1) and 2cosA2=1+sinA1sinA ---(2)



I have understood upto this far well,



Now they have broke the them into quadrants :



In 1st quadrant :



2sinA2=1+sinA1sinA

2cosA2=1+sinA+1sinA



In 2nd quadrant :



2sinA2=1+sinA+1sinA
2cosA2=1+sinA1sinA



In 3rd quadrant :



2sinA2=1+sinA1sinA

2cosA2=1+sinA+1sinA



In 4th quadrant :



2sinA2=1+sinA1sinA
2cosA2=1+sinA+1sinA



Now, In knew the ALL-SINE-TAN-COSINE rule but still I am not able to figure out how the respective signs are computed in these (above) cases.


Answer



The easiest way of computing the signs is to make them match; we know that sin x > 0 if 0 < x < π and that cos x > 0 if -π/2 < x < π/2. Knowing whether sin A is greater than 0 or less than zero tells you whether 1sinA is greater or less than 1+sinA; that in turn lets you figure out what the overall sign on all of the right-hand terms is, and each quadrant corresponds to one of the four positive/negative pairs on the right-hand terms.



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