Find the limit of $\lim\limits_{x\rightarrow0}\frac{x}{\tan x}$
Clearly, since the limit takes the form of $\frac{0}{0}$, one should try L'Hopital's Rule. If we apply L'Hopital's Rule, the problem is that $\frac{d(\tan x)}{dx}=\cot x$, and $\cot(0)$ is undefined. Thus, we cannot find a limit using L'Hopital's Rule.
My problem set suggests that this question can be answered using little more than L'Hopital and Cauchy's Mean Value Theorem. Not sure how to proceed. Please help.
Answer
No, the derivative of $\tan x$ with respect to $x$ is $\sec^2x$, not $\cot x$. But you don’t need l’Hospital’s rule:
$$\frac{x}{\tan x}=\frac{x}{\sin x}\cdot\cos x\;,$$
and you should know the limits of both factors as $x\to 0$.
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