The task is to lim. n is an integer. I've tried to use Stolz theorem, but that doesn't seem to give any result.
Thank you for your help.
Answer
By ratio test
\frac{{x}^{100(n+1)}}{(n+1)!}\frac{n!}{{x}^{100n}}=\frac{x^{100}}{n+1}\to 0
then
\lim_{n\to\infty} \frac{{x}^{100n}}{n!}=0
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