So I've been trying to figure out how to prove the following.
Let (an) be a sequence of positive numbers such that ∞∑n=1an=∞, and define sn=n∑i=1ai. Then ∞∑n=1ansn=∞ as well.
I can prove it by comparing it to ∫∞11xdx if the sequence an is bounded by some M, but that's as far as I've been able to get.
Answer
Since sn→+∞ when n→∞, for each n⩾1 there exists some finite m>n such that sm⩾2sn. In particular, m∑k=n+1aksk⩾m∑k=n+1aksm=1−snsm⩾1/2. Thus, the rests of the series ∑kaksk do not converge to zero, QED.
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