Calculate:
limx→0+tanx⋅√tanx−sinx⋅√sinxx3√x
I don't know how to use L'Hôpital's Rule.
I tried to make tanx=sinxcosx for the term √tanx.
How to find limh→0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...
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