Wednesday, 4 January 2017

real analysis - The definitions of limit infimum and limit supremum




I have begun reading Rosenthal's "A First Look to Rigorous Probability Theory" and in order to reinforce my calculus background I am studying through the appendix section. Here he defined the limit of a sequence of real numbers as limnxn=x if for each 0<ϵ there is a natural number N such that it is |xxn|<ϵ for n>N.



Then the limit infimum and supremum are defined as lim infnxn=limninfknxk and lim supnxn=limnsupknxk.




  1. My first question is about the interpretation of the limit infimum and limit supremum definitions. It looks to me like they are defined as the limits of sequences as well. For example, for the infimum, one can define a sequence an=infknxk where xn was already a sequence of real numbers. Then the limit infimum is the limit of the sequence an , limnan, so the infimums of the subsequences xk where kn are converging if the limit exists. It is the similar for the supremum. Is my interpretation correct here?


  2. It is said the limit infimum and supremum do always exist, though they can be infinite. I did not understand this; why it is so?


  3. In the book it is stated that the limit limnxn exists if and only if it is lim infnxn=lim supnxn. I could not prove this to myself. How can it be shown that this statement is true?





Thanks in advance.


Answer



These are answers to the secondary questions
in the comments after my answer to the original question;
I cannot put the answers in comments,
because the size of a comment is limited.



The second question.
Let (xn) be a sequence taking values in the set {0,1,2,,9},

and a:=lim infnxn.
If 0 appears infinitely many times in the sequence, then a=0.
If 0 appears only finitely many times, but 1 appears infinitely often, then a=1.
And so on.
This is a slick answer.
It is entirely another matter to answer the question with a definite value
for a particular given sequence, such as the sequence of digits after the comma
in the decimal expansion of π.
Well, if you can prove that the digit 0 appears infinitely many times
in the decimal expansion of π, then you have a=0, and so on;

in this case it takes a serious theoretical effort to determine the lim inf.



As for the third question,
let (xn) be a sequence of real numbers
such that a:=lim infnxn is a real number (that is, $-\inftySince the sequence of infima an:=infknxn is increasing
(meaning that mn implies aman -- I hate "nondecreasing"),
the limit a=limnan is actually the supremum: a=supnan.
Let a1a and $a'We claim that there exists m such that xna for every nm:
since a=supnan, there exists m such that ama;

but then xnama for every nm.
Now let a1>a, and set a:=12(a+a1); we have $aIn this case we claim that given any m
there exists nm such that $x_nsince $a_m=\inf_{k\geq m} x_k\leq aWe have proved that a is the largest of all real numbers a1
with the property that
for every $a'

No comments:

Post a Comment

real analysis - How to find limhrightarrow0fracsin(ha)h

How to find limh0sin(ha)h without lhopital rule? I know when I use lhopital I easy get $$ \lim_{h\rightarrow 0}...